![SOLVED: point) Derive the orthogonality relations on P, P] for the functions cos ML sin MI using the trig identities sin(u) sin (v) Z[cos(u v) cos(u + v)] cos(u) cos(v) E[cos(u v) + SOLVED: point) Derive the orthogonality relations on P, P] for the functions cos ML sin MI using the trig identities sin(u) sin (v) Z[cos(u v) cos(u + v)] cos(u) cos(v) E[cos(u v) +](https://cdn.numerade.com/ask_previews/25fa9e8f-0f4d-4854-9866-ee969056ee65_large.jpg)
SOLVED: point) Derive the orthogonality relations on P, P] for the functions cos ML sin MI using the trig identities sin(u) sin (v) Z[cos(u v) cos(u + v)] cos(u) cos(v) E[cos(u v) +
![5. if the expression cos^2(pi/11)+cos^2((2pi)/11)+cos^2((3pi)/11)+cos^2 ((4pi)/11)+cos^2((5pi)/11) has the value equal to p/q in it lowest from ; then find (p+q) 5. if the expression cos^2(pi/11)+cos^2((2pi)/11)+cos^2((3pi)/11)+cos^2 ((4pi)/11)+cos^2((5pi)/11) has the value equal to p/q in it lowest from ; then find (p+q)](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/642550062_web.png)
5. if the expression cos^2(pi/11)+cos^2((2pi)/11)+cos^2((3pi)/11)+cos^2 ((4pi)/11)+cos^2((5pi)/11) has the value equal to p/q in it lowest from ; then find (p+q)
![Values of trigonometric functions of arcs pi/6 pi/4 and p/3, The values of the trigonometric functions of arcs that are multipliers of 30 degrees (pi/6) and 45 degrees (pi/4 Values of trigonometric functions of arcs pi/6 pi/4 and p/3, The values of the trigonometric functions of arcs that are multipliers of 30 degrees (pi/6) and 45 degrees (pi/4](http://www.nabla.hr/TrigFValuesT.gif)
Values of trigonometric functions of arcs pi/6 pi/4 and p/3, The values of the trigonometric functions of arcs that are multipliers of 30 degrees (pi/6) and 45 degrees (pi/4
![trigonometry - How prove $\left(\sum\cos{\frac{2k-1}{p}\pi }\right)\cdot\left(\sum\cos{\frac{2k-1}{p}\pi}\right)$ - Mathematics Stack Exchange trigonometry - How prove $\left(\sum\cos{\frac{2k-1}{p}\pi }\right)\cdot\left(\sum\cos{\frac{2k-1}{p}\pi}\right)$ - Mathematics Stack Exchange](https://i.stack.imgur.com/5IciQ.jpg)