Let 2sin^2x+3sinx-2>0a n dx^2-x-2<0(x is measured in radians). Then x lies in the interval (pi/6,(5pi)/6) (b) (-1,(5pi)/6) (-1,2) (d) (pi/6,2)
SOLUTION: By translation, graph y=sin(x-&#960;/6) for 0 <= x <= 2&#960;. Label all with coordinates intercepts and the peak and the valley.
Solved] Rewrite sin(x+7π/6) in terms of sin x and cos x . | Course Hero
At what point does sin (x + PI/6) + cos (x + PI/6) attain maximum value in the interval (0,PI/2)? - YouTube
find x if cos-1+ sin-1 (x/2) = pi/6 please dont give ny links i din't understand - Maths - Inverse Trigonometric Functions - 11249319 | Meritnation.com
SOLVED: If f(x) = ∫^sin x0 √(1 + t^2) dt and g(y) = ∫^y3 f(x) dx, find g”(π/ 6).
Evaluate the Definite Integrals `Int_(Pi/6)^(Pi/3) (Sin X + Cosx)/Sqrt(Sin 2x) Dx` - Mathematics | Shaalaa.com
cos^(-1)x+sin^(-1)(x/2)= pi/6` - YouTube
Solved For part (b), I don't understand why 5pi/6 and 3pi/2 | Chegg.com